jumlah deret geometri tak hingga ½+⅓+ adalah

jawab
deret geometri
1/2  + 1/3 + ....

a= 1/2
r = 1/3: 1/2 = 1/3 x 2/1 = 2/3

s~ = a/( 1- r)

s~ = (1/2) / (1 - 2/3)

s~ = 1/2 / 1/3

s~ = 1/2 x3/1 

s~ = 3/2

a = 1/2

r = U2 / U1
r = 1/3 / 1/2
r = 2/3

S∞ = a / (1-r)

S∞ = 1/2 / ( 1 - 2/3 )

S∞ = 1/2 / 1/3

S∞ = 1/6