suatu garis melalui titik (3,2)dan (5,6). Tentukan persamaan garisnya? #tlong d jawab

(y-2) / (6-2) = (x-3)/(5-3)
(y-2) / 4 = (x-3) / 2
2 (y-2) = 4(x-3)
2y - 4 = 4x - 12
2y = 4x - 8
y = 2x - 4

x1=3y1=2x2=5y2=6

[tex] \frac{y-y1}{y2-y1} = \frac{x-x1}{x2-x1} \\ \frac{y-2}{6-2} = \frac{x-3}{5-3} \\ \frac{y-2}{3}= \frac{x-3}{2} \\ (kali silang) \\ 2(y-2)=3(x-3) \\ 2y-4=3x-9 \\ 2y-3x-4+9=0 \\ 2y-3x+5=0 (PERSAMAAN)[/tex]

atau 
2y-3x+5=02y=3x-5y=3/2x-5/2