salah satu akar persamaan( a-1)xkuadrat -18x+6+10a=0 adalah dua kali akar yg alin adalah

(a-1)x²-18x+6+10a = 0
a = (a-1)
b = -18
c = 6+10a

x1 = 2x2

x1+x2 = -b/a
= 18/a-1
3x2 = 18/ a-1
x2 = 6/ a-1

x1.x2 = c/a
= 6+10a/ a-1
2x2² = 6+10a/ a-1
x2² = 3+5a/ a-1
6²/(a-1)² =3+5a/ a-1
36/a-1 = 3+5a
36 = (a-1)(5a+3)
= 5a²-2a-3

5a²-2a-39 = 0
(5a + 13 )(a - 3) = 0
a = -13/5 atau a = 3

a = 3
2x²-18x+36 = 0
x²- 9x + 18 = 0

x2 = 6/ 3-1
= 3

x1 = 3.2
= 6