Matematika

Pertanyaan

tolong dong syp yg bisa? bsok di kumpul
tolong dong syp yg bisa? bsok di kumpul

1 Jawaban

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    1.
    [tex]( {64 \times 27)}^{ \frac{1}{3} } \\ = ( {2}^{6} \times {3}^{3} )^{ \frac{1}{3} } \\ = {2}^{6 \frac{1}{3}} \times {3}^{3 \frac{1}{3} } \\ = {2}^{2} \times 3 \\ = 4 \times 3 \\ = 12[/tex]

    2.
    [tex] \frac{10 \times \sqrt{10} \times 5 \sqrt{20} }{5 \sqrt{20} \times \sqrt{5} } \\ = \frac{50 \sqrt{200} }{5 \sqrt{100} } \\ = \frac{500 \sqrt{2} }{50} \\ = 10 \sqrt{2} [/tex]

    3.
    [tex] \frac{5}{3 \sqrt{3} - \sqrt{2} } \\ = \frac{5}{3 \sqrt{3} - \sqrt{2} } \times \frac{3 \sqrt{3} + \sqrt{2}}{3 \sqrt{3} + \sqrt{2} } \\ = \frac{15 \sqrt{3} + 5 \sqrt{2} }{27 - 2} \\ = \frac{5(3 \sqrt{3} + \sqrt{2}) }{25} \\ = \frac{3 \sqrt{3} + \sqrt{2} }{5} [/tex]

    4.
    [tex](2 \sqrt{3 } + \sqrt{2} )^{2} \\ = (2 \sqrt{3 } + \sqrt{2} )(2 \sqrt{3 } + \sqrt{2} ) \\ = 12 + 2 \sqrt{6} + 2 \sqrt{6} + 2 \\ = 14 + 4 \sqrt{6}[/tex]

    5.
    [tex]( {a}^{ \frac{4}{9} } \div {a}^{ \frac{3}{4} } )^{ - 5} \\ = ( {a}^{ \frac{16 - 27}{36} } ) ^{ - 5} \\ = {a}^{ \frac{ - 11}{36} \times - 5 } \\ = {a}^{\frac{55}{36} } \\ = {a}^{1 \frac{19}{36} }[/tex]

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