tolong bantu jawab soal no. 2 ya.....mau dikumpulin buat hari senen besok

F1x = 20 N
F2x = 20 cos 60
F2y = 20 sin 60
F3x = 30 cos 60
F3y = 30 sin 60
Fx = F1x-F2x-F3x
20-20 cos 60-30 cos 60
20-20*1/2-30*1/2
20-10-15= -5
Fy= F2y-F3y
20 sin 60-30 sin 60
20*1/2√3 - 30*1/2√3
10√3-15√3 = -5√3
Resultan= √Fx²+Fy²
√(-5)²+(-5√3)²
√25+(25*3)
√25+75= √100= 10