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Pertanyaan

Berapa ph larutan 200 ml KOH 0,01 M?

1 Jawaban

  • OH- = Mb.b = 0.01 × 1 = 10^-2
    pOH = -logOH- = -log10^-2 = 2
    pH = 14 - pOH = 14 - 2 = 12

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