tentukan invers f (x) = 11 x + 6

f(x) = y
[tex] f(y)^{-1} [/tex] = x
y = 11x + 6
11x = -y +6
x = [tex] \frac{-y + 6}{11} [/tex]
[tex] f(y)^{-1} = \frac{-y + 6}{11} \\ f(x)^{-1} = \frac{-x+ 6}{11}[/tex]