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Pertanyaan

hitung pH dari larutan HCN 0,4 M (Ka HCN =10^-5)

1 Jawaban

  • [H+] = √Ka.Ma
    [H+] = √10^-5.4.10^-1
    [H+] = √4.10^-6 = 2.10^-3 M
    pH = -log[H+] = -log[2.10^-3] = 3-log2

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