Jika larutan 5 gram garam dicampur 250mL air,Berapa Konsentrasi larutan Garam yang terjadi,dalam satuan g/L

K = [tex] \frac{m.z.p}{v.z.p} [/tex] = [tex] \frac{5}{0,25} \frac{x}{x} \frac{100}{100} = \frac{500}{25} = 20 gr/L[/tex]

zat terlarut/zat pelarut = 5 gram/250 ml : 1000 = 5/0,25 = 20 g/l