Sederhanakan penjumlahan dan pengurangan?

bagian a.
[tex]3 \sqrt{2} + \sqrt{2} + 5 \sqrt{2} \\ = (3 + 1 + 5) \sqrt{2} \\ = 9 \sqrt{2} [/tex]
bagian b.
[tex]2 \sqrt{3} + \sqrt{27} + \sqrt{12} \\ = 2 \sqrt{3} + \sqrt{9 \times 3} + \sqrt{4 \times 3} \\ = 2 \sqrt{3} + 3 \sqrt{3} + 2 \sqrt{3} \\ = (2 + 3 + 2) \sqrt{3} \\ = 7 \sqrt{3} [/tex]
bagian c
[tex]5 \sqrt{6} + \sqrt{24} - \sqrt{6} \\ = 5 \sqrt{6} + \sqrt{4 \times 6} - \sqrt{6} \\ = 5 \sqrt{6} + 2 \sqrt{6} - \sqrt{6} \\ = (5 + 2 - 1) \sqrt{6} \\ = 6 \sqrt{6} [/tex]
bagian d
[tex] \sqrt{45} + \sqrt{80} - \sqrt{5} \\ = \sqrt{5 \times 9} + \sqrt{16 \times 5} - \sqrt{5} \\ = 3 \sqrt{5} + 4 \sqrt{5} - \sqrt{5} \\ = (3 + 4 - 1) \sqrt{5} \\ = 6 \sqrt{5} [/tex]
bagian e
[tex]6 \sqrt{7} - \sqrt{28} + \sqrt{63} \\ = 6 \sqrt{7} - \sqrt{4 \times 7} + \sqrt{9 \times 7} \\ = 6 \sqrt{7} - 2 \sqrt{7} + 3 \sqrt{7} \\ = (6 - 2 + 3) \sqrt{7} \\ = 7 \sqrt{7} [/tex]