3 1per2 + 4 2per3 - 3 1per4 dikali 2per5

[tex]3 \frac{1}{2} + 4 \frac{2}{3} - 3 \frac{1}{4} \times \frac{2}{5} \\ = (3 + 4) + ( \frac{3 + 4}{6}) - \frac{13}{4} \times \frac{2}{5} \\ = 7 \frac{7}{6} - \frac{13}{10} \\ = \frac{49}{6} - \frac{13}{10} \\ = \frac{245 - 39}{30} \\ = \frac{206}{30} \\ = 6 \frac{26}{30} \\ = 6 \frac{13}{15} [/tex]