Tolong dijawab ya Kaka Kaka please no 9 sama 10 ya,dan cara nya. Minta tolong ya thanks

9. L arsir= L besar-L kecil
L besar= π×r²
=22/7×21×21
=22×21×3
=1386 cm²
L kecil= π×r²
=22/7×14×14 (14=>2/3×21)
=22×14×2
=616 cm²

L arsir= 1386-616
=770 cm²

10. diket:
debit selang 1= 30liter/mnt
debit selang 2= 540000cm³/jam
waktu=1,25jam= 1 jam 15 menit
ditanyakan: volume air?
jawab:
volume air= volume selang 1+ volume selang 2

volume selang 1= debit×waktu
=30×1jam 15menit
=30×75
=2250liter

volume selang 2= debit×waktu
=540000cm³/jam× 1jam 15mnt
=540dm³/jam×1,25 (dm³=liter)
=675liter

volume air= 2250+675
=2925liter
semoga membantu:)

9. r O bsr = 42cm ÷ 2 = 21cm
→ r O kcl = 2/3 × 21 = 14cm

Luas O bsr → πr²
<=> 22/7 × 21 × 21
<=> 1.386 cm²
Luas O kcl → πr²
<=> 22/7 × 14 × 14
<=> 616 cm²

Maka, luas yg diarsir
→1.386 cm² - 616 cm²
<=> 770 cm²

10. Volume dr selang A → Debit × waktu
<=> 30 lt / jam × 1,25 jam
→ 1,25 jam
→(1×60 = 60mnt) + (25/100 ×60 = 15mnt)
→ 1,25 jam = 60+15 = 75 mnt
<=> 30 lt / m × 75 m
<=> 2.250 lt

Volume dr selang B → Debit × waktu
<=> 540.000 cm³/jam × 1,25 jam
→ 540.000 cm³ ÷ 1.000 = 540 lt
<=> 540 lt × 1 ¼ jam
<=> 675 lt

Maka, volume = 2.250 lt + 675 lt = 2.925 lt

Jdkn jwbn tercerdas yh:)