jumlah tak terhingga dari deret geometri.-3 per 4 + 9 per 14+ 19per 16- 27 per 64... pke caranya yh

jawab

deret tak hingga

-3/4 + 9/14 + 9/16 - 27/64 + ...=

= 9/14  + (-3/4 + 9/16 - 27/64 + ... )
= 9/14 + s~

cari s~  dari (-3/4 + 9/16 - 27/64 +....)
a= -3/4
r = - 3/4
s~ = a/(1-r)
s~ = - (3/4) / (1 - (- 3/4))
s~ = - (3/4) / ( 1 + 3/4)
s~ = - (3/4) / (7/4)
s~ = - 3/7

9/14 + s~  = 9/14 - 3/7 =  9/14 - 6/14 = 3/14