bila f(x) x2 (2x+3)pangkat 3,maka turunan pertama fungsi f(x) adalah f'=??? #mohon jawaban nya master mtk dan caranya ya :)

jawab,

f(x) =
[tex] {x}^{2} (2x + 3 {)}^{2} [/tex]
maka turunan fungsi :

f(x)' = U'.V + U.V'

U = X^2
V = (2x + 3)^2

U' = 2x


V' =
[tex] n {v}^{n - 1} {u}^{ l} [/tex]

V' = 2(2x + 3).2
= 8x + 12
= 8

f(x)' = 2x(2x + 3 )^2 + x^2(8)
= 2x(2x^2 + 12x + 9) + 8x^2
= 4x^3 + 24x^2 + 18x + 8x^2
= 4x^3 + 16x^2 + 18x
= 12x^2 + 32x + 18.

semoga membantu
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