Selesaikan persamaan kuadrat di bawah ini dengan mengunakan rumus abc ! A. X²+4x-5=0 B. X²-6x+5=0

Penjelasan dengan langkah-langkah:

A.

x² + 4x - 5 = 0

x₁,₂ = [-b ± ✓(b² - 4ac)]/2a

x₁,₂ = [-4 ± ✓(4² - 4(1)(-5)]/2(1)

x₁,₂ = [-4 ± ✓36]/2

x₁,₂ = [-4 ± 6]/2

x₁,₂ = - 2 ± 3

x₁ = - 2 + 3

x₁ = 1

x₂ = - 2 - 3

x₂ = - 5

HP = { -5, 1 }

B.

x² - 6x + 5 = 0

x₁,₂ = [-b ± ✓(b² - 4ac)]/2a

x₁,₂ = [-(-6) ± ✓((-6)² - 4(1)(5)]/2(1)

x₁,₂ = [6 ± ✓16]/2

x₁,₂ = [6 ± 4]/2

x₁,₂ = 3 ± 2

x₁ = 3 - 2

x₁ = 1

x₂ = 3 + 2

x₂ = 5

HP = { 5, 1 }