mohon bantuannya kak , secepatnya
Matematika
Jordanniron5
Pertanyaan
mohon bantuannya kak , secepatnya
1 Jawaban
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1. Jawaban Anonyme
Kelas 11 Matematika
Bab Limit
lim (3 - √(2x + 3)) / (x² - 9)
x→3
= lim (3 - √(2x + 3))/(x² - 9) . (3 + √(2x + 3))/(3 + √(2x + 3))
...x→3
= lim (9 - (2x + 3))/((x² - 9) . (3 + √(2x + 3))
...x→3
= lim (6 - 2x)/((x² - 9) . (3 + √(2x + 3))
...x→3
= lim (-2 (x - 3))/((x + 3)(x - 3)(3 + √(2x + 3))
...x→3
= -2/((3 + 3) . (3 + √(2 . 3 + 3))
= -2/(6 . (3 + √9))
= -1/(3 . (3 + 3))
= -1/(3 . 6)
= -1/18