Jika f(x)= 1 per x-2 dan g(x) = log x. Maka (f(g(x))) pangkat min 1 =

jawab

fungsi invers

f(x) = 1/ ( x- 2)
g(x)=  log x

f og(x) =  f { g(x) }
fog(x) = f (log x)
fog(x) = 1/ (log x -2)

y = 1/ (logx - 2)
y (log x - 2) = 1
y log x - 2y = 1
y log x = 2y +1
log x^y = 2y + 1

x^y = 10^(2y +1)
x = 10^(2y +1)/y
x = 10^(2+1/y)

( f(g(x))⁻¹=  10^(2 + 1/x)