Suatu muatan 20uC berapa medan listrik pada jarak 2cm !

F = K . Q / r

k = 9.10^9
q = 20 uC = 2.10^-5C
r = 2 cm = 2.10^-2m


F = 9.10^9 x 2.10^-5/2.10^-2
F = 9.10^4/10^-2
F = 9.10^4-(-2)
F = 9.10^6 N