tolong bantu no 19 trims

Materi : Listrik
Sub bab : Gaya Coulomb

Diketahui :
Fa = F
Q1a = Q
Q2a = Q
ra = d
Q1b = 2Q
Q2b = Q
rb = 2d

Ditanya :
Fb = ?

Penyelesaian :
F = k. Q1Q2 / r²
Fr² = k. Q1Q2
Fr²/Q1Q2 = k

Fara²/Q1aQ2b = Fbrb²/Q1bQ2b
Fd²/Q. Q = Fb.(2d)²/(2Q)(Q)
Fd²/Q² = Fb. 4d²/2Q²
F = 4Fb/2
F = 2Fb
Fb = ½F

Jadi, gaya coulombnya menjadi ½F

Jawaban : A
semoga membantu
# sharing is caring #
-vin