Nilai Ph dari HClO4 0,015M

HClO4 ~ H+ + ClO4-
0,015 M ~ 0,015 M

[tex]0.015 = {15 \times 10}^{ - 3} [/tex]

[tex]ph \: = - log(h + ) \\ = - log(15 \times {10}^{ - 3} ) \\ = 3 - log15[/tex]
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