jika a dan b akar akar persamaan kuadrat seperti gambar diatas mohon dibantu buat materi belajar

Kelas 10 Matematika
Bab Persamaan Kuadrat

(p - 2) x² + 4x + (p + 2) = 0
a = p - 2; b = 4; c = p + 2

αβ² + βα² = -20
αβ (β + α) = -20
c/a . -b/a = -20
(p + 2)/(p - 2) . -4/(p - 2) = -20

** -20 : -4 = 5 **

p + 2 = 5 . (p - 2)²
p + 2 = 5 . (p² - 4p + 4)
5p² - 20p - p + 20 - 2 = 0
5p² - 21p + 18 = 0
(5p - 6) (p - 3) = 0
5p - 6 = 0
5p = 6
p = 6/5

atau

p - 3 = 0
p = 3

Jadi, p = 6/5 atau p = 3