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Pertanyaan

PH Ba( OH )2 0,030 M

1 Jawaban

  • [OH-] = b x Mb
    = 2 x 0,03
    =0,06
    = 6 x 10^-2

    pOH = - log [OH-]
    = - log 6x10^-2
    = 2 - log 6
    = 2 - 0,778
    = 1,222

    pH = 14 - pOH
    = 14- 1,222
    =12,788

    Maaf kalo salah

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