PH Ba( OH )2 0,030 M
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ironarya4197
Pertanyaan
PH Ba( OH )2 0,030 M
1 Jawaban
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1. Jawaban Diannaid
[OH-] = b x Mb
= 2 x 0,03
=0,06
= 6 x 10^-2
pOH = - log [OH-]
= - log 6x10^-2
= 2 - log 6
= 2 - 0,778
= 1,222
pH = 14 - pOH
= 14- 1,222
=12,788
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