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Jawab Nh . √72-√32+√8=

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  • [tex] = \sqrt{72} - \sqrt{32} + \sqrt{8} \\ = \sqrt{36 \times 2} - \sqrt{16 \times 2} + \sqrt{4 \times 2} \\ = 6 \sqrt{2} - 4 \sqrt{2} + 2 \sqrt{2} \\ = (6 - 4 + 2) \sqrt{2} \\ = 4 \sqrt{2} [/tex]

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  • √72- √32+√8
    √36x2 -√16x2 +√4x2
    6√2-4√2+2√2
    =4√2

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