Matematika

Pertanyaan

1-cos^2 x/sin^2 x -1=1-sec^2 x

1 Jawaban


  • [tex] \frac{1 - { \cos}^{2}x }{ { \sin }^{2}x - 1 } = 1 - { \sec}^{2} x \\ \\ \frac{1 - { \cos}^{2}x }{ { \sin }^{2}x - 1 } = \frac{1 - { \cos}^{2}x}{ - \cos^{2}x} \\ = \frac{ \cos^{2}x}{ \cos^{2}x} - \frac{1}{ \cos^{2}x} \\ = 1 - { \sec}^{2} x [/tex]

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