3 akar 6 - akar 2 per 4 akar 3 + akar 2

[tex] = \frac{3 \sqrt{6} - \sqrt{2} }{4 \sqrt{3} + \sqrt{2} } \times \frac{4 \sqrt{3} - \sqrt{2} }{4 \sqrt{3} - \sqrt{2} } \\ = \frac{12 \sqrt{18} - 3 \sqrt{12} - 4 \sqrt{6 } + 2 }{48 - 2} \\ = \frac{36 \sqrt{2} - 6 \sqrt{3} - 4 \sqrt{6} + 2}{46} \\ = \frac{1}{23} (18 \sqrt{2} - 3 \sqrt{3} - 2 \sqrt{6} + 1)[/tex]