soal mengenai limit:) tolong bantuya lim.......3 - [tex] x^{2} [/tex] x-->3  ------------------------- ..........4 - [tex] \sqrt{ x^{2} + 7 } [/tex]

[tex] \lim_{x \to 3} \frac{3- x^{2}}{4- \sqrt{ x^{2}+7}} [/tex]

[tex]= \lim_{x \to 3} \frac{3- x^{2}}{4- \sqrt{ x^{2}+7}} \times \frac{4+ \sqrt{ x^{2}+7}}{4+ \sqrt{ x^{2}+7}} [/tex]

[tex]= \lim_{x \to 3} \frac{(3- x^{2})(4+ \sqrt{ x^{2}+7})}{4- (x^{2}+7)} [/tex]

[tex]= \lim_{x \to 3} \frac{(3- x^{2})(4+ \sqrt{ x^{2}+7})}{4- x^{2}-7} [/tex]

[tex]= \lim_{x \to 3} \frac{(3- x^{2})(4+ \sqrt{ x^{2}+7})}{-3- x^{2}} [/tex]

[tex]= \lim_{x \to 3}\,\,\,\, -(4+ \sqrt{ x^{2}+7})[/tex]

[tex]= \lim_{x \to 3}\,\,\,\, -4- \sqrt{ x^{2}+7}[/tex]

[tex]Masukkan\,\,nilai\,\,x\,\,sehingga :[/tex]

[tex]= -4- \sqrt{ x^{2}+7}[/tex]

[tex]= -4- \sqrt{3^{2}+7}[/tex]

[tex]= -4- \sqrt{9+7}[/tex]

[tex]= -4- \sqrt{16}[/tex]

[tex]= -4- 4[/tex]

[tex]= -8[/tex]