Matematika

Pertanyaan

lim x -> -y

tan x + tan y/(x^2 - y^2/-2y^2)(1 - tan x tan y)

2 Jawaban

  • Mapel Matematika
    Bab Limit

    = Lim tan x + tan y/(x^2 - y^2/-2y^2)(1 - tan x tan y)
    x ➡-y

    = Lim 1/(x^2 - y^2/-2y^2) x (tanx+tany/1-tanxtany)
    x ➡-y

    = Lim 1/(x^2 - y^2/-2y^2) (tan (x+y)
    x ➡-y

    =( 1/y^2-y^2/-2y^2) (Tan(-y + y)
    = 0 (0)
    = 0
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