lim x -> -y tan x + tan y/(x^2 - y^2/-2y^2)(1 - tan x tan y)
Matematika
Mikhail17
Pertanyaan
lim x -> -y
tan x + tan y/(x^2 - y^2/-2y^2)(1 - tan x tan y)
tan x + tan y/(x^2 - y^2/-2y^2)(1 - tan x tan y)
2 Jawaban
-
1. Jawaban Flawlyara
Mapel Matematika
Bab Limit
= Lim tan x + tan y/(x^2 - y^2/-2y^2)(1 - tan x tan y)
x ➡-y
= Lim 1/(x^2 - y^2/-2y^2) x (tanx+tany/1-tanxtany)
x ➡-y
= Lim 1/(x^2 - y^2/-2y^2) (tan (x+y)
x ➡-y
=( 1/y^2-y^2/-2y^2) (Tan(-y + y)
= 0 (0)
= 0 -
Pertanyaan Lainnya