Nilai x yang memenuhi persamaan 3x+2y-6z=12 5x-4y+2z=0 6X+z=26 adalah....

Persamaan I
3x + 2y - 6z =12 [x2] 6x + 4y - 12z =24
5x - 4y + 2z =0 [x1] 5x - 4y + 2z =0
————————— +
11x -10z =24

Persamaan II
=>11x - 10z = 24 [x1] 11x - 10z = 24
6x + z = 26 [x2] 60x + 10z = 260
——————— +
71x = 284
x = 4

x= 4 masukkan ke persamaan II

=>11x - 10z = 24
= 11 . 4 - 10z =24
= 44 - 10z = 24
= - 10z = - 20
= z = 2

=> x= 4, z= 2, masukkan ke persamaan I

= 5x - 4y +2z =0
= 5 . 4 - 4y + 2 . 2 =0
= 24 - 4y =0
= - 4y = -24

- 24
y= ——— = 6.
- 4


Jadi => nilai : x= 4, y= 6, z=2
Nilai x => 4.
Semoga membantu :) Follow aku ya :)